Re: [hylafax-users] request for help with regex for dialrules

[marthter <marthter@xxxxxxxx>]

Rance Hall wrote  on 22/06/05 05:03 PM:

> ive got my dial rules about 75% done
>
> but im stuck on two points (which by the way, turn out to be the same 
> problem)
>
> I have two variables in my dialrules one is called localareas and the 
> other is localexchanges
>
> both have data of the format "123|456|789"
>
> the issue is that we have a long distance access code that must be 
> dialed after the main number is dialed if the call is long distance
>
> based on the results of my dialrules tests I have the system building 
> a complete phone number with the ld access code correctly
>
> assume that hylafax dialrules can get me to the point where I have 
> every number entered as 19185551212111
>
> where the last three numbers are the ld access code we have discussed, 
> also note that the ldsuffix is a variable in the dialrules script as well
>
> I need a transformation that will return the existing value except for 
> ldsuffix if the phone number matches the following regex
>
> ^1918(${localexchanges})[0-9]{4}4${ldsufix} assume 918 is the local 
> area code, then assume that localechanges has the list of local 
> exchanges, if the string expression matches this, then what needs to 
> be returned is the original string minus the last ldsuffix variable
>
> this is what I have and what it does:
>
> ^1918(${localexchanges})[0-9]{4}4${ldsufix}= \1
>
> This only returns the local exchange I need it to return the 
> localexchange and the number.
> This seemed easier than a bunch of if then else statements to 
> construct the number in one pass.
Based on vague recollections...

I think the \1 is returning only the localexchange because of the round 
brackets around ${localexchanges}

I think if you put another set of round brackets around [0-9]{4} then 
you would have a second block of matched stuff to play with after the = 
sign which you would access with \2.  In other words, I think, just 
maybe, this is what you want:

^1918(${localexchanges})([0-9]{4})4${ldsufix}= \1\2

Or extend your existing pair of round brackets to include everything you 
want to use as  \1 collectively and leave out \2.

Though I can't say that I see any use for the extra 4 you have before 
the second $.  Just a typographical error?  Or else I'm missing 
something about how your long distance code works.

Hope that helps.

> can someone help me fix this please.
>
> Thank you

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