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Re: y2k problem in faxcron/recvstats/xferstats
"Frans E. van Dorsselaer" <frans@bia-bv.demon.nl> writes:
> I use hylafax 4.0pl2 on Suse Linux 6.1, but the problem
> appears to be present in the current CVS as well.
> Since 1/1/2000 faxcron reports _all_ faxes ever sent in
> the receive stats, transmission stats, and error log report.
>
> The receive/transmit stats are done in scripts called
> recvstats and xferstats respectively, I fixed those (patch attached).
> The problem is due to calculation of the age based on
> YY * 365 + ..., where YY is a 2-digit year representation.
> Fix includes YY < 70 check.
>
> The error reports are filtered from faxcron itself, using
> awk. I'm not good at awk, and I haven't tracked down the
> problem further.
>
> Bye,
>
> Frans van Dorsselaer
> frans@bia-bv.demon.nl
>
>
> --- orig.recvstats Mon Jan 3 00:11:45 2000
> +++ recvstats Mon Jan 3 00:12:20 2000
> @@ -157,7 +157,10 @@
> #
> function cvtDateTime(s)
> {
> - yday = substr(s,7,2)*365 + substr(s,4,2) - 1;
> + yday = substr(s,7,2);
> + if (yday < 70)
> + yday += 100;
> + yday = yday*365 + substr(s,4,2) - 1;
> mon = substr(s,0,2) + 0;
> for (i = 0; i < mon; i++)
> yday += daysInMonth[i];
> --- orig.xferstats Mon Jan 3 00:03:55 2000
> +++ xferstats Mon Jan 3 00:11:08 2000
> @@ -186,7 +186,10 @@
> #
> function cvtDateTime(s)
> {
> - yday = substr(s,7,2)*365 + substr(s,4,2) - 1;
> + yday = substr(s,7,2);
> + if (yday < 70)
> + yday += 100;
> + yday = yday*365 + substr(s,4,2) - 1;
> mon = substr(s,0,2) + 0;
> for (i = 0; i < mon; i++)
> yday += daysInMonth[i];
It seems that you run Alpha or other 64-bit box :-) On the 32-bit
processors the above code gives incorrect result due to an overflow. And
it also contains an older bug : substr(s,0,2) instead of substr(s,1,2). It
means that xferstats/recvstats _never_ generated correct results. I wonder
why nobody noticed that before.
So, here is the function with my fixes applied:
function cvtDateTime(s)
{
yday = substr(s,7,2);
if (yday < 70)
yday += 30;
else
yday -= 70;
yday = yday*365 + substr(s,4,2) - 1;
mon = substr(s,1,2) + 0;
for (i = 0; i < mon; i++)
yday += daysInMonth[i];
return yday*FULLDAY + cvtTime(substr(s,10) ":00");
}
Hope to hear from you soon,
Dmitry